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3aa7c3b587b446837df26d64b4ed76e5e6ad63e6
Using grep "devel\s\+3:" to find at least one whitspace is not portable on all grep versions; not all grep versions understand "\s" as a "whitespace". Use a literal TAB followed by SPACE. The + as a qualifier for "one or more" is not a basic regular expression; use egrep instead of grep. Signed-off-by: Torsten Bögershausen <tboegi@web.de> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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